In the given figure, OP=OQ, P=60° and R=40°. Find OSR. please help
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Step-by-step explanation:
Solution
We know, the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle
Hence,In given circle,
∠POR=2∠PQR
Therefore ∠POR=2×40
o
=80
o
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