Question

In the given figure Out is the centre of the circle and AB is parallel to CD. AB=10cn and Distance between the chords AB and CD is 17cm.If the radius of the circle is 13cm, find length of the chord CD. ​

Answer 1

Step-by-step explanation:

AP WILL BE HALF OF AB SINCE PERPENDICULAR FROM CENTRE BISECTS CHORD

AO^2 =AP^2 +PO^2

13^2 = 5^2 +PO^2

so, PO=12cm

Distance b/w chords is 17 so, OQ=5CM

Same applies with triangle COQ

CO^2 =OQ^2 +CQ^2

13^2 = 5^2 +CQ^2

CQ=12cm

CQ IS HALF OF CD

so. CD =24 Cm