Question

In the given figure, P is a point on the side BC of a ∆ABC. Prove that:
(AB + BC + AC) < 2AP
no spam or absurd answers or i will report

Answer 1

Answer:

Step-by-step explanation:

In ∆CDA, (CD + DA) > AC.

4. As above.

5. 2(AB + BC + CD + DA) > 2(AC + BD).

5. Adding the equations in statements 1, 2, 3 and 4.

6. (AB + BC + CD + DA) > (AC + BD). (Proved)

6. Cancelling the common factor 2.