Question

In the given figure, P is any point on the diagonal AC of the parallelogram ABCD. Show that ar(ΔADP) = ar (ΔABP).

Answer 1

Answer:

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Answer 2

Answer:

draw the diagonal AC and BD intersecting o and draw DP perpendicular to Ao and join PB

proof in triangle obp PO is the median

area of triangle OPD is equal to area of triangle on ----------1

in triangle abd Ao is the median

area of triangle Ado is equal to area of triangle Aob-------2

subtracting equation 1 and 2

area of triangle APO=Abp

Step-by-step explanation:

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