Question

In the given figure, PA = PB, QA = QB. Prove that
PQ is the bisector of ZAPB and ZAQB.​

Answer 1

Answer:

Construction: Join PQ which meets AB in D. Proof: P is equidistant from A and B. ∴ P lies on the perpendicular bisector of AB. Similarly, Q is equidistant from A and B. ∴ Q lies on perpendicular bisector of AB. ∴ P and Q both lie on the perpendicular bisector of AB. ∴ PQ is perpendicular bisector of AB. Hence, locus of the points which are equidistant from two fixed points, is a perpendicular bisector of the line joining the fixed points.

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