Question

in the given figure pa, perpendicular to ab ,qb perpendicular to ab and pa = qb prove that ∆Oap congruent ∆ Obq .is oa =ob​

Answer 1

According to question

Given PA= QB

OA=OB

PA perpendicular to AB => angle PAO =90°

QB perpendicular to AB => angle QBO =90°

Triangle OAP =~ triangle OBQ (SIDE-ANGLE-SIDE)