Math, asked by Debrajpro, 10 months ago

- In the given figure, PA touches the circle with centre
O at A. PD bisects ZAPB. Prove that AD = AE​

Answers

Answered by makarandchakradev
6

Answer:

by drawing perpendicular bisected, it proves both chord are congruent by hypo. test. then by c.s.c.t. ad=ae

Answered by suhasri
3

Answer:

AD=AE

Step-by-step explanation:

Using, alternate segment theorem,

<CAP=<CBA

<ADP=<CBA + <CPE

<DEA=<EAP + <EPA

=<CBA + <EPA

=<ADP

=<ADE

So, triangle, ADE is isosceles, AD=AE

Q.E.D

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