Question

In the given figure, PAQ is a tangent to the circle with center O at a point A. If angle OBA = 45°, find the value of angle BAQ and angle ACB.​

Answer 1

Step-by-step explanation:

OB=OA (radius)

angle OAB = angle OBA

angle OAB = 45°

OAQ=90° (radius perpendicular to tangent)

OAQ = OAB + BAQ

=45°+BAQ=90°

BAQ=45°

ACB= AOB/2

AOB + OAB + OBA =180°

45+ 45+AOB=180

AOB=90

ACB 90/2

ACB=45°