Question

in the given figure , parallelogram ABCD and PBCSQ are given . If R is a point on PB ,then show that ar(triangle QRC )=1/2 area of parallelogram ABCD.​

Answer 1

Step-by-step explanation:

PBCQ And ABCD are parallelograms

(Given)

They have common base BC and lies between same parallels AQ And BC

SO, ar(ABCD)=ar(PQBC)

-(i)

Now, ΔQRC and llgm PBCQ lies on commom base BC and between common parallels' BC And AQ

So, ar(Δ QRC)=ar(llgm PQBC)

From (i):-

ar(Δ QRC)=ar(llgm ABCD)

HENCE,PROVED.

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