Question

.
А
In the given figure PELE
AC + BC and DE LAB.
prove that to E=AC
E E
с
DE
B
BC
С c​

Answer 1

Answer:

Ex 7.1, 6 In the given figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. Given: AC = AE AB = AD ∠ BAD = ∠

Step-by-step explanation:

Ex 7.1, 6 In the given figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. Given: AC = AE AB = AD ∠ BAD = ∠ EAC To prove: BC = DE Proof: Given that ...