Question

In the given figure PL+ OA and PM + OB such that OL = OM
prove that . i) triangle OLP parallel to triangle OMP
ii) PL =PM
iii) <LOP = MOP​

Answer 1

Step-by-step explanation:

Given

PL⊥OA , PM⊥OB and PL=PM

To Prove:

△PLO≅△PMO

Proof:

In △PLO and △PMO

∠PLO=∠PMO=90

o

PO=PO (common side)

PL=PM (given)

∴ △PLO≅△PMO by the SAS congruence property.

Answer 2

Step-by-step explanation:

hope it is correct