Question

in the given figure PM parallel to QT find the value of x​

Answer 1

x= 90°

With respect to ∆ RMS,

angle RMP = exterior angle

=> angle RMP = angle MRS + angle MSR

=> 120° = 30° + angle MSR

=> angle MSR = 90°

angle MSR = x (corresponding angle)

=> x = 90°

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