In the given figure, points S, T and U are the midpoints of PQ, QR and PR respectively. Ifpv
QR, then prove that SVTU is a cyclic quadrilateral.
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In the given figure, S and T are the mid-points of sides PR and PQ respectively of ΔPQR. If ar (ΔPQR)=48cm
2
, then find ar (ΔTSQ).
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ANSWER
If area of △PQR=48c.m
2
If we consider △QSP, then
area of this triangle is 24c.m
2
because QS is the median, median divide triangle in equal areas,
So, area of △QSP=24c.m
2
Now in △QSP again 'ST' is median
So, area of △QST= half of △QSP=
2
1
ar(△QSP)
∴ ar△QST=12c.m
2
→ option− C
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