In the given figure POQ is diameter and AP=AQ .Find< APQ.
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In the above figure first of all join OR
Now, from the figure it is seen that
△OBP≅△ORP
Then, ∠BOP=∠ROP=x
Now, from the figure it is also seen that
△OAQ≅△ORQ
Since AOB is straight line,
∠AOB=180 ⁰
∴x+x+y+y=180 ⁰
∴2x+2y=180 ⁰
∴2(x+y)=180 ⁰
∴(x+y)=90 ⁰
∴∠POQ=90 ⁰
→ Hence OP and OQ are perpendicular to each other.
DISHA HERE
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