Math, asked by sudheerpadikal, 11 days ago

In the given figure, POR is a line. Find the value of a

Answers

Answered by xxMahiraxx
0

∴∠POQ+∠QOR=180

∴∠POQ+∠QOR=180 o

∴∠POQ+∠QOR=180 o

∴∠POQ+∠QOR=180 o ⇒(3a+5)

∴∠POQ+∠QOR=180 o ⇒(3a+5) o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25)

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a=

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200 o

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200 o ⇒a=40

∴∠POQ+∠QOR=180 o ⇒(3a+5) o +(2a−25) o =180 o ⇒5a=180 o +20 o =200 o ⇒a= 5200 o ⇒a=40 o

Answered by nikhilrajgone2008
2

Answer:

(a) 40o We know that, when the sum of the measures of two angles is 180o, the angles are called supplementary angles. (3a + 5)o + (2a – 25)o = 180o 3a + 5 + 2a – 25 = 180o 5a – 20 = 180o 5a = 180o + 20 5a = 200 a = 200/5 a = 40oRead more on Sarthaks.com - https://www.sarthaks.com/790828/in-fig-por-is-a-line-the-value-of-a-is-a-40-b-45-c-55-d-60?show=790833#a790833

Step-by-step explanation:

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