Question

in the given figure potential difference between A and B is 100 V. potential difference across 6 micro F capacitor is​

Answer 1

Given:

Potential difference between the terminals A and B is 100 V. A combination capacitors in a circuit has been provided.

To find:

Potential difference across the 6 $\mu F$ capacitor.

Concept:

First , we need to simplify the circuit by assigning potential drop along each capacitor. Then we can easily understand if the capacitors are present in series or parallel combinations.

Refer to te attached diagram.

Calculation:

After simplification of circuit , 6 micro F and 4 micro F capacitors are in parallel whereas the 10 micro-F capacitor is in series.

Hence net capacitance of circuit will be :

$\therefore \: C_{net} = \dfrac{10 \times (6 + 4)}{10 + ( 6 + 4)}$

$= > \: C_{net} = 5 \: \mu F$

Now charge between A and C will be :

$= >q = \: C_{net} \times voltage$

$= >q = \:5 \times 100$

$= >q = \:500 \: C$

Now , potential difference across 6 micro-F capacitor will be :

$\therefore \: V_{6 \mu} = \dfrac{500}{(6 + 4)}$

$= > \: V_{6 \mu} = \dfrac{500}{(10)}$

$= > \: V_{6 \mu} = 50 \: V$

So final answer is:

$\boxed{ \bold{ \huge{\: V_{6 \mu} = 50 \: V}}}$

Answer 2

Answer:

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