Question

in the given figure PQ and PR are tangents to a circle with centre o such that angle QPR equal to 50 degree then find angle oqr​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

In quadrilateral PQOR, ∠P+∠PQO+∠PRO+∠QOR=360°

But ∠PQO=∠PRO=90°

(Tangent is perpendicular to radius at point of contact)

Thus, 50° +90° +90° +∠QOR=360°

So, ∠QOR=130°

In triangle OQR, ∠OQR+∠ORQ+∠QOR=180°

Hence, 2.∠OQR+∠QOR=180°

(because, ∠OQR=∠ORQ; (since OQ=OR, radii ))

Thus, 2.∠OQR+130°

=∠180°

So, ∠OQR=25°