In the given figure, PQ and PR are tangents to the circle with Centre O such that ∠QPR = 50°, then find ∠OQR.
Answers
Answered by
11
In quad. PQOR,
∠R+ ∠O+ ∠Q+ ∠P = 360
∠P + ∠O = 90
∠O = 130
Now,
In ∆ROQ,
∠RQO + ∠QOR + ∠ORQ = 180°
Now as the sides OQ = RO because of radius of same circle... Hence.... OQR = 25°
∠R+ ∠O+ ∠Q+ ∠P = 360
∠P + ∠O = 90
∠O = 130
Now,
In ∆ROQ,
∠RQO + ∠QOR + ∠ORQ = 180°
Now as the sides OQ = RO because of radius of same circle... Hence.... OQR = 25°
Attachments:
Charuta123:
How will Angle OQR be formed???
Similar questions