Question

in the given figure, PQ and PR are two tangets to a circle with centre O. If <QPR =46°.then calculate <QPR​

Answer 1

Step-by-step explanation:

hope it help u.......................

Answer 2

$\huge\underline\mathbb\red{Solution:-}$

Step-by-step explanation:

As,

we know that when a radius touches a tangent at the point of contact the angle formed is always 90°

Therefore,

Angle OQP=Angle ORP=90°

Now,

The sum of angles of a quadrilateral is 360°

OQP+ORP+RPQ+QOR=360°

90+90+46+QOR=360°

QOR=134°

Thanks......