in the given figure PQ and Rs intersect each other at O if angle 75° find the value of ABC
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4b = a (Vertically opposite angles)
2c = 75 + b
Therefore
75+b+4b= 180 ( R.S Straight Angle )
75+5b = 180
5b = 105
angle b = 21°
angle c = 75+ 21
= 96°
angle a = 4(21)
= 84°
2c = 75 + b
Therefore
75+b+4b= 180 ( R.S Straight Angle )
75+5b = 180
5b = 105
angle b = 21°
angle c = 75+ 21
= 96°
angle a = 4(21)
= 84°
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