Question

In the given figure, PQ and TS are perpendiculars to QS. R is the mid-point
of QS and angle PRT = 90°. If PQ = 9 cm, QS =
24 cm, TS = 16 cm, find PT.
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Answer 1

Answer:

PT = 25 cm

Step-by-step explanation:

given: PQ = 9 cm

QS=24cm

QR=RS = 12 cm

TS = 16 cm

angle PRT =90 degree

PQ and TS are perpendicular to QS thus angle Q and angle S are of 90 degree.

solution :

in triangle PQR, angle Q = 90 degree

therefore by Pythagoras theorem

(PQ) square +(QR) square =(PR) square.....(substitute values)

thus we get, PR= 15 cm

now in triangle TSR, angle S=90 degree

therefore by Pythagoras theorem

(TS) square +(SR) square = (TR) square.......(substitute values)

thus we get,TR =20 cm

in triangle TRP, angle R=90 degree

therefore by Pythagoras theorem

(RT) square +(PR) square = (PT) square

thus we get,

400+225=(PT) square

625= (PT) square

thus PT = 25 cm ........ taking square root on both sides.

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Answer 2

Answer:

see the paper and solve

Step-by-step explanation:

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