In the given figure PQ II AB and PR II AC. Prove QR II BC
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Given that : - PQ ॥ AB & PR ॥ AC.
To prove : - QR ॥ BC
Proof : -
Now,
In ∆AOB,
OP/PA = OQ/QB....(i) [By Basic proportionality theorem]
Similarly, In ∆AOC,
OA/PA = OR/RC .....(ii) [By Basic proportionality theorem.]
From (i) & (ii), we get,
OQ/BQ = OR/RC
Therefore, QR ॥ BC . [By converse of Basic proportionality theorem.]
Hence, proved.
Given that : - PQ ॥ AB & PR ॥ AC.
To prove : - QR ॥ BC
Proof : -
Now,
In ∆AOB,
OP/PA = OQ/QB....(i) [By Basic proportionality theorem]
Similarly, In ∆AOC,
OA/PA = OR/RC .....(ii) [By Basic proportionality theorem.]
From (i) & (ii), we get,
OQ/BQ = OR/RC
Therefore, QR ॥ BC . [By converse of Basic proportionality theorem.]
Hence, proved.
hafeezhtech:
thanks a lot, I asked the same question before, but I didn't find the correct answer to it. thanks for answering my doubt :)
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