in the given figure PQ II RS Angle PAB=70° and angle ACS = 100° Determine angle ABC, BAC and CAQ.
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abc=30,bac=70,caq=80
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PQ||RS (GIVEN)
PAB=70°
ACS=100°
TO DETERMINE ANGLE ABC,BAC and CAQ
1. FOR ABC
ACS=ABC=100°(CORRESPONDING ANGLES)
2.FOR BAC
ABC+BCA+CAB=180°(ANGLE SUM PROP.OF A TRIANGLE)
100°+BCA+70°=180°
170°+BCA=180°
BCA=180°-170°
BCA=10°
3.FOR CAQ
A=Q=70°(CORRESPONDING ANGLES)
PAB=70°
ACS=100°
TO DETERMINE ANGLE ABC,BAC and CAQ
1. FOR ABC
ACS=ABC=100°(CORRESPONDING ANGLES)
2.FOR BAC
ABC+BCA+CAB=180°(ANGLE SUM PROP.OF A TRIANGLE)
100°+BCA+70°=180°
170°+BCA=180°
BCA=180°-170°
BCA=10°
3.FOR CAQ
A=Q=70°(CORRESPONDING ANGLES)
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