Question

In the given figure PQ is a chord of a circle with centre O and radius 5cm. If or is perpendicular to PQ and OR= 4om, then the length of chord PQ is​

Answer 1

Answer:

OP=5(radius) OR =4

using pythogorus theorem

PR^2=5^2-4^2

=25-16=9

PR=3cm

PQ=2*3=6cm

Answer 2

Using Pythagoras theoram,

= H² = P² + B²

= 5² = 4² + B²

= 25 = 16 + B²

= 25 - 16 = B²

= √9 = B

= 3 = B = PR

PQ = 2 × PR

PQ = 2 × 3

PQ = 6 cm

Your diagram is wrong, correct diagram is in the attachments above.