In the given figure PQ is a chord of a circle with centre O and radius 5cm. If or is perpendicular to PQ and OR= 4om, then the length of chord PQ is
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Answer:
OP=5(radius) OR =4
using pythogorus theorem
PR^2=5^2-4^2
=25-16=9
PR=3cm
PQ=2*3=6cm
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Using Pythagoras theoram,
= H² = P² + B²
= 5² = 4² + B²
= 25 = 16 + B²
= 25 - 16 = B²
= √9 = B
= 3 = B = PR
PQ = 2 × PR
PQ = 2 × 3
PQ = 6 cm
Your diagram is wrong, correct diagram is in the attachments above.
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