Question

In the given figure PQ is a line. Ray OR is
perpendicular to line PQ. OS is another ray lying
between rays OP and OR.
Prove that ZROS=1/2(ZQOS-ZSOP
​

Answer 1

Answer:

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Answer 2

Answer:

Answer

∠ROS=90

∘

−∠POS−(i)

∠QOS=∠QOR+∠ROS=90

∘

+∠ROS

⇒90

∘

=∠QOS−∠ROS−(ii)

Substituting (ii) in (i) we get

∠ROS=∠QOS−∠ROS−∠POS

⇒2∠ROS=∠QOS−∠POS

⇒∠ROS=

2

1

(∠QOS−∠POS)