Question

. In the given figure , PQ is a tangent at point B, to the circle with centre 0. If angle AOB = 100°
then find angle
ABP​

Answer 1

Given that

∠ AOB = 100°

Since OA = OB

So ∠ OAB = ∠ OBA = 40°

Since PQ is tangent on the circle. So OB is perpendicular to PQ.

So,

∠ OBP = 90°

∠ OBA + ∠ ABP = 90°

∠ ABP = 90 – ∠ OBA

∴ ∠ ABP = 90° – 40°

∴ ∠ ABP = 50°