In the given figure PQ is parallel to RS angle ACS =100, Determine angle BAC ,C and angle ABC.
it's urgent please help
Attachments:

Answers
Answered by
2
Answer:
mark me as brain list
and follow me
Attachments:

Answered by
3
Answer:
∠ABC = 70°, ∠BAC = 30°, ∠C = 80°
Step-by-step explanation:
here, ∠ACS + ∠ACB = 180° by linear pair
= 100° + ∠ACB = 180°
= ∠ACB = 180° - 100°
= ∠ACB = 80°
now, ∠ACB = ∠CAQ PQ║RS and alternate interior angles
so, ∠CAQ = 80°
∵∠CAQ + ∠BAP + ∠BAC = 180° by linear pair
= 80° + 70° +∠BAC = 180°
= ∠BAC = 180° - 150°
= ∠BAC = 30°
∴ ∠ABC + ∠BAC + ∠ACB = 180° by angle sum property
= ∠ABC + 30° + 80° = 180°
= ∠ABC = 180° - 110°
= ∠ABC = 70°
hence, ∠ABC = 70°, ∠BAC = 30°, ∠C = 80°.
hope it help.
Similar questions