Question

in the given figure pq is parallel to rs, angle trs= 105 degree, and rtp=30 degree, value of x please

Answer 1

Step-by-step explanation:

x is 135 degree.

this is the right answer.

Answer 2

x = 135 Degrees
GIVEN: PQ is parallel to RS, angleTRS = 105 degree and RTP =30 degree.
TO FIND: Value of angle X
SOLUTION:

According to the figure,

We Extend the parallel lines SR and QP.

Such that,

TOP becomes a Triangle.

And as we know,

Angle ROP = 180 - ( 105 + 30)

                 = 180 - 135

                 = 45 degrees

Now,

Using the Straight Line Property,

Angle ROP + Angle POS = 180 Degrees

Angle POS = 180 - Angle ROP

                  = 180 - 45

                  = 135 Degrees

Since,

Angles POS = Angle TPQ = x

x = 135 Degrees

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