in the given figure PQ is parallel to RS find the value of x and y
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angle A=180°-120°=60°
so, angle C=x°=180°-(35°+60°)
or, x°=85°
as RS and PQ is parallel x°=angle CDB
so, angle CDB=85°
thus, γ°=180°-85°
=95°
so, angle C=x°=180°-(35°+60°)
or, x°=85°
as RS and PQ is parallel x°=angle CDB
so, angle CDB=85°
thus, γ°=180°-85°
=95°
deekshapandey:
thanks
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Find Angle A:
Sum of adjacent angles on a straight line is 180º
∠A = 180 - 120 = 60º
Find Angle x:
Sum of angles in a triangle is 180º
∠x = 180 - 35 - 60 = 85º
Find Angle D (∠CDB):
Corresponding angles on parallel lines are equal
∠D = x = 85º
Find Angle y:
Sum of adjacent angles on a straight line is 180º
∠y = 180 - 85 = 95º
Answer: x = 85º and y = 95º
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