In the given figure PQ is perpendicular to AB, AQ =QB, angle PAC =42° angle c =68° Find angle ABC
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Answer:
M is the midpoint of PQ
M is the midpoint of AB
Step-by-step explanation:
Given:
PA = QB ............(1)
In ΔAPM and ΔBQM,
∠M=∠M (common)
∠A=∠B=90
∠P=∠Q
ΔAPM and ΔBQM are equiangular
By AAA similarity,
ΔAPM and ΔBQM are similar.
Their corresponding sides are proportional.
\frac{AP}{BQ}=\frac{PM}{QM}=\frac{AM}{BM}\\\\using\:(1)\\\\1=\frac{PM}{QM}=\frac{AM}{BM}\\\\\frac{PM}{QM}=1\\\\PM=QM
PA = QB
PA/QB = 1
AM/ BM = MP/MQ = 1
This implies, M is the midpoint of PQ
\frac{AM}{BM}=1\\\\AM=BM
This implies, M is the midpoint of AB...
that's solved
thanks
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