In the given figure PQ is perpendicular to QR,STllQR,QT bisects angle PQR, find the measures of QST, angle SQT and angle STQ.If angle PRQ=70degree then find angle QTR
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In △s PTR and PTQ
∠PTR=∠PTQ (each 90∘)
PQ=PR (Given)
PT=PT (Common side)
Thus, △PTR≅△PTQ
Hence, ∠TPR=∠TPQ (By CPCT)
or, PT bisects ∠QPR
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