In the given figure, PQ =PR amd Qs=SR, prove that
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Step-by-step explanation:
(i) since, PQ=PR
Therefore, <Q=<R
Now , in ∆ PQS and ∆ PRS
PQ= PR
QS=SR
<Q=<R
Hence,∆ PQS ~= ∆PRS ( BY SSS)........(1)
(ii) Since , ∆PQS~= ∆ PRS
=> <PSQ=PSR (by cpct )
Also , <PSQ+ < PSR = 180° ( Linear pair)
2 <PSQ = 180°
=> < PSQ=90° = <PSR ( Hence proved)
ALSO FROM (1)
and < QPS= < RPS ( By CPCT)
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