Question

in the given figure PQ PR and BC are the tangents to the circle the circle at x if PQ is equal to 7 centimetre then the perimeter of triangle PBC is​

Answer 1

Answer:

$\large\boxed{\sf{14\;\;cm}}$

Step-by-step explanation:

Concept Map:-

• The lengths of tangents drawn from an external point of a circle are equal

Now, in the question

CR and XR are two tangents drawn from an external point C

⇒ CR = XC

Also, BQ and XB are two tangents drawn from an external point B

⇒ BQ = XB

Again, PR and PQ are two tangents drawn from an external point P

⇒ PR = PQ = 7 cm

Now, Perimeter of ΔPBC = PC + PB + BC

= PC + PB + (BX + CX)

= PC + CX + BX + PB

= (PC + CR) + (BQ + PB) (°.° CX = CR, BQ = BX)

= PR + PQ

= 7 + 7 (°.°PR = PQ = 7 CM ]

= 14 cm