in the given figure PQ, PR and ST, are tangents to the same circle. if angle P is equal to 40 degree and Angle qrt is equal to 75 find a ,b and c.
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Here you go!
All the best for math exam tomorrow, I'm writing it too!
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shakibr704:
but angle qrt is equal to angle rqa how!!!
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Given,
In the given figure PQ, PR and ST, are tangents to the same circle. ∠P = 40° and ∠QRT = 75°
To Find,
∠a, ∠b and ∠c
Solution,
PQ = PR (tangents)
∴ 40° + a + a = 180°
2a = 180 - 40
∠a = 70°
Joining QT, we get
∠QRT = ∠RQA = 75°
(Angle mad by chord and tangent = Angle in opposite segment)
In ΔQRT,
∠TQR = 180 - (70 + 75) = 180 - 145 = 35°
∠c = ∠TQR = 35°
Since SR = ST, ΔRST is isosceles.
∴ ∠b = 180 - 35 - 35 = 180 - 70 = 110°
Hence, ∠a = 70°, ∠b = 110° and ∠c = 35°.
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