In the given figure, PQ = PS and PR ⊥ QS, prove that
(i) PQR ≅ PSR
(ii) QR = RS
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Answer:
angle PQR~anglePSR _(given)
side PQ~side PR
SidePR~SidePR -(common side)
angle PQR~angle PSR by Hypoteuse test
then side Qr~sidePR
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