Question

In the given figure, PQ, QR, and RS are of same length. Semi-circles are
drawn on PQ and QS as diameters. If PS is the diameter of the circle of
radius 9 cm, find the area of the shaded region.
22
(Take n =
Р
22)​

Answer 1

Answer:

6.25cm

Step-by-step explanation:

Perimeter of the shaded region = (perimeter if semicircle with dia=PS)−

(perimeter if semicircle with dia=QS)+

(perimeter if semicircle with dia=PQ)$$

PS=6cm

PQ=QR=RS

PQ+QR+RS=6

∴PQ=QR=2

=(π)(

2

PS

)−π(

2

QS

)+(π

2

PQ

)

=(π)(

2

6

)−π(

2

4

)+(π

2

2

)

=3π−2π+π

=2π cm

=6.25 cm