In the given figure, PQ, QR, and RS are of same length. Semi-circles are
drawn on PQ and QS as diameters. If PS is the diameter of the circle of
radius 9 cm, find the area of the shaded region.
22
(Take n =
Р
22)
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divyanshsrivastava90:
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2
Answer:
6.25cm
Step-by-step explanation:
Perimeter of the shaded region = (perimeter if semicircle with dia=PS)−
(perimeter if semicircle with dia=QS)+
(perimeter if semicircle with dia=PQ)$$
PS=6cm
PQ=QR=RS
PQ+QR+RS=6
∴PQ=QR=2
=(π)(
2
PS
)−π(
2
QS
)+(π
2
PQ
)
=(π)(
2
6
)−π(
2
4
)+(π
2
2
)
=3π−2π+π
=2π cm
=6.25 cm
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