In the given figure, PQ || RS and PQ=RS. Prove that ∆ POQ ≅ ∆SO
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Given:-
PQ∥RS
To prove:-
△POQ∼△SOR
Proof:-
In △POQ and △SOR
∠POQ=∠SOR[∵Vertically opposite angles]
∠P=∠S[∵As PQ∥RS, Alternate angles]
∠Q=∠R[∵As PQ∥RS, Alternate angles]
Using AAA similarity function criteria,
△POQ∼△SOR
Hence proved.
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