Question

In the given figure, PQ=RS, PS=QR. Prove that ∆PQR ≅ ∆PSR please and fast

Answer 1

$\underline{\bigstar{\sf \ Given:}}$

• PQ = RS
• PS = QR

$\underline{\bigstar{\sf \ To\:Prove:}}$

• ∆PQR ≅ ∆PSR

$\underline{\bigstar{\sf \ Proof:}}$

In ∆ PQR and ∆ PSR

PQ = RS ( Given)

PS = QR ( Given)

PR = PR ( Common)

➡ ∆PQR ≅ ∆PSR ( By SSS congruence rule)

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