In the given figure PQ||ST then find the value of X and y .
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Answer:
x = 65° and y = 50°
Step-by-step explanation:
∠TSO = 130°
∵ ∠SOQ = 130° (alternate interior angles are equal)
∴ ∠SOQ + ∠SOB = 180° (linear pair)
130° + ∠SOB = 180°
∠SOB = 180° - 130°
∠SOB = 50°
y = 50° (∠SOB is y)
_______
∠PQR + ∠OQR = 180° (linear pair)
115° + ∠OQR = 180°
∠OQR = 180° - 115°
∠OQR = 65° - - - - - 1
∠QOR = ∠SOB (vertically opposite angles are equal)
∠QOR = 50° - - - - - 2
∠OQR + ∠QOR + ∠ORQ = 180° (angle sum property of triangle)
Considering 1 and 2,
65° + 50° + ∠ORQ = 180°
115° + ∠ORQ = 180°
∠ORQ = 180° - 115°
∠ORQ = 65°
x = 65° (∠ORQ is x)
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