In the given figure, ∆PQR is a right angled triangle,
right angled at P and PTSU is a square. If QS = 5 cm
and SR = 10 cm, then the area of ∆PQR is equal
sm
s
om
R
(1) 90 cm2
(3) 30 cm2
(2) 180 cm2
(4) 45 cm2
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The answer is (3) 30 cm2
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