Question

In the given figure, PQR is a right triangle, right angled at P. QP is extended to T and TS|QR intersecting PR at N.
If anglePNS = 120°,find:
¡) angleQTS
¡¡)anglePQR
¡¡¡) angle QRP​

Answer 1

Step-by-step explanation:

Q=360-(90+90+120)

Q=360-(180+120)

Q=60°

Q+T+S=180

60+90+T=180

T=180-150=30°

<QTS,=30°//

<PQR=60°//

<SNR=180-120=60

<NSR=90°

<SRN=30°

<SRN=<QRP=30°

Answer 2

hope it's helped u ♥️❤️