In the given figure, PQR is an equilateral triangle, AB ║ PR and PR is produced to D such that RD = QA. Prove that BD bisects AR.
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Given :
∆PQR is an equilateral triangle
AB ║ PR
RD = QA.
To Find :
BD bisects AR
Solution :
Since we are given that , ∆PQR is an equilateral triangle. Therefore all sides of ∆PQR will be equal to 60°. mathematically ;
→∠P + ∠Q + ∠R = 60°
Now, we are also provided that AB ║ PR Therefore :
→∠P = ∠R [Corresponding angles]
∴ ∠P = 60°
So, by observation we found that ∠P and ∠Q is equal to 69° therefore, the third side of the ∆ will also be 60°.
→∠Q + ∠A + ∠B = 60°
∴ ∆QAB is an equilateral traingle
→QB = AB
→QA = RD
→∠R = ∠M [Alternate angels]
∴ ∆ABM ≅ ∆RDM [AAS Property]
∴ AM = RM
∴BD bisects AR.
Hence Proved !
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U will get in the pic
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