Question

in the given figure, ∆PQR is right angled triangle right angled at R and RS parralel to PQ. also, anglen P=55°. find (1) angle PRS (2) angle QRS (3) angle RQS

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Answer 1

Step-by-step explanation:

1. angle PRS+RPS+PSR=180

PRS+55+90=180

PRS+145=180

PRS=35

2. angle QRP= QRS+SRP

90=QRS+35

QRS=90-35

QRS=55

3. RQS+QRS+RSQ=180

RQS+55+90=180

RQS=180-145

RQS=35