in the given figure PQRS is a cyclic quadrilateral in which PS=RS sqr is x and pqs is 60 the value of x is a 30 b 60 c 75 d 80
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In △TPS and △TRQ
∠PST=∠RQT
∠SPQ=∠QRT
[∵ exterior angle of cyclic quadrilateral is equal to the interior opposite angle]
∠T=∠T (common)
∴△TPS−△TRQ (By AA)
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60° is your answer ..........
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