In the given figure PQRS is a parallelogram, PQ is produced to U, and T is th emid point of QR . If SR=10, find the length of PU
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To prove:
- QO = OR i.e. ST bisects RQ.
Proof:
- PQRS is a parallelogram.
PQ || RS
Now, PQ || RS and transversal QR intersects them∠1 = ∠2 …(i) (alternate interior angles)
Now PQRS is a parallelogram
⇒ PQ = RS⇒ QT = RS …(ii
QT = PQ (given)
Thus in ΔQOT and ΔSOR, we have∠1 = ∠2 [using (i)]
∠3 = ∠4 (vertically opposite angles)
and
QT = RS [using (ii)]
ΔQOT = ΔROS (by AAS congruency rule)
⇒ QO = OR
⇒ O is the mid-point of QR
⇒ ST bisects RQ
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