Question

In the given figure, PQRS is a quadrilateralia<br />which pq= qr and qr=sr. Diagonal PR and qs<br />instersect each other at o.<br />show that<br />i) PQR =PSR<br />ii)POQ =POS​

Answer 1

Answer:

Answer

We know that in any triangle the sum of any two sides is greater than the third side.

In △PQO,PQ+QO>PQ→(1)

In △SOP,SO+PO>PS→(2)

In △SOR,SO+OR>RS→(3)

In △QOR,QO+OR>QR→(4)

Adding equations (1) , (2) , (3) & (4) , we get

2(PO+OQ+SO+OR)>PQ+QR+RS+SP

PQ+QR+RS+SP<2(PQ+OR+SO+OQ)

PQ+QR+RS+SP<2(PR+SQ)

solution