In the given figure, PQRS is a rectangle, if PRQ=30° , find the value of PQS
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QS & PR intersect each other at O which is the mid point. because we know Diagonals of rectangle bisects each other.
Also we know Diagonals of the rectangle is equal. so dividing them by 2 we will get OQ= OR
hence OQR = ORQ = 30°
We know PQR = 90°
PQS + SQR = PQR
so PQS = PQR - SQR = 90° - 30° = 60°
Also we know Diagonals of the rectangle is equal. so dividing them by 2 we will get OQ= OR
hence OQR = ORQ = 30°
We know PQR = 90°
PQS + SQR = PQR
so PQS = PQR - SQR = 90° - 30° = 60°
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Given:
Angle PRQ=30°
To find:
The angle PQS
Solution:
The angle PQS is 60°.
The angles P, Q, R, and S are right angles in the rectangle.
The diagonals of PQRS are of equal length and bisect one another.
PR=QS and PO=OR, OQ=OS.
In ΔQOR, OQ=OR
So, angle ORQ=angle OQR (Angles corresponding to equal sides)
angle ORQ=angle OQR=30°
In rectangle PQRS, Angle Q=90°
Angle Q=angle PQS+angle OQR
90°=angle PQS+30°
Angle PQS=60°
Therefore, the angle PQS is 60°.
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