Question

In the given figure, PQRS is a rectangle. If PS=8 cm and SR=4 cm, then find the area of ∆ABC.​

Answer 1

Step-by-step explanation:

area of ACP= 1\2bh

= 1\2×8×8

= 32

area of rectangle SBCP= bh

= 88

= 64

therefore,area of triangle= ABC

= 64-32= 32

Answer 2

Area of triangle ABC=$16cm^2$

Step-by-step explanation:

PS=8 cm

SR= 4 cm

Area of rectangle=$length\times breadth$

Using the formula

Area of rectangle PQRS=$8\times 4=32 cm^2$

We know that when two parallelogram are formed on the same base and between same parallel lines then their area are equal.

Therefore,

Area of PQRS=Area of PQAB=32 square cm

When a parallelogram and a triangle area formed on the same base and between same parallel lines then

Area of parallelogram=2 times the area of triangle.

Therefore,

Area of triangle ABC=$\frac{32}{2}=16cm^2$

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