In the given figure, PQRS is a rectangle.
QS = QT, angle QTS = 50°. Find angle RST and
angle RQT
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Given : PQRS is a rectangle.
QS = QT, angle QTS = 50°
Reflex PST = 260°
To Find : angle RST and angle RQT
Solution:
Reflex PST = 260°
=> ∠PST =360° - 260° = 100°
∠PST = ∠PSR + ∠RST
∠PSR = 90° as PQRS is a rectangle
=> 100° = 90° + ∠RST
=> ∠RST = 10°
QS = QT
=> ∠QST = ∠QTS
=> ∠QST = 50°
∠QST = ∠QSR + ∠RST
=> 50° = ∠QSR + 10°
=> ∠QSR = 40°
=> ∠SQR = 50° ( as sum of angles in ΔSRQ = 180° and ∠SRQ = 90°)
∠QST = ∠QTS = 50°
∠QST + ∠QTS + ∠SQT = 180° Sum of angles of triangles
=> ∠SQT = 80°
∠SQT = ∠SQR + ∠RQT
=> 80° = 50° + ∠RQT
=> ∠RQT = 30°
∠RST = 10° and ∠RQT = 30°
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