Question

In the given figure ,pqrs is a square lawn with side PO = 42m . Two circular flower beds are there on the sides PS and QR with centre O, the intersection of its diagonals , find the total area of the two flower beds (shaded parts).​

Answer 1

Answer:

Given 2 shapes: Square and semicircle

The circle is cut in half to form a semi-circle. The square is placed between the two semi-circles.

Two semi-circles are the shaded part.

We will find the area of the shaded part which forms 1 circle.

$\sf \: Area \: of \: a \: circle = \bf {πr {}^{2} }$

The side of the square lawn serves as the diameter of the circle. Radius is half of the diameter.

$\sf \: r = \frac{d}{2} = \frac{42}{2} \: = \pink{ \bf{ 2m}}$

$\pink{ \sf \: Area \: of \: circle}$

$\sf \: = 3.14×(21) {}^{2} =3.14×441= \bf{1384.74m {}^{2}}$

The area of the shaded parts is 1,384.74 square meters.

Hence, This is Answer.

Answer 2

Answer:—

• 1386 m².

Step-by-step explanation:—

In the figure as we are shown,

There are two semi-circles at PS and QR.

The length of the side, PQ = 42 m.

PQRS is a square.

Therefore,

The total Area of the two flower beds are given by,

Area of circle having diameter = 42 m

So,

Area of circle = πr²

As,

• Diameter, D = 42 m
• Radius, r = D/2 = 21 m

So,

Area of circle is,

$= > \pi r^{2}=\frac{22} {7} \times (21)^{2} \\ = > 22\times 21\times 3 \\ = > \: 1386\,m^{2}$

Therefore,

The area of two flower beds is 1386 m².